Cargo Securement Working-Load-Limit Check

Aggregate WLL vs. the half-cargo-weight requirement, pass/fail, and the minimum tiedown count for the article length.

Run the calculator

Example

You enter

Cargo weight (lb) 8000
Number of tiedowns 4
WLL per tiedown (lb, marked) 1500
Article length (ft) 16

You get

Aggregate WLL 6000 lb
Required (1/2 cargo weight) 4000 lb

Details, formula, and sources

Per FMCSA 49 CFR 393.100-393.136; WLLs user-supplied from the marked hardware.

Aggregate WLL = number of tiedowns x per-tiedown WLL; required >= 0.5 x cargo weight; minimum tiedown count from the length/weight rule (>= 1 per 10 ft, >= 2 for articles over 5 ft or 1100 lb).

FMCSA 49 CFR 393.100-393.136 cargo securement (aggregate-WLL and tiedown-count rules), by name.

Free at ecfr.gov; FMCSA enforces.

Math aid for personal verification. The ELD on the truck and the carrier tariff are the legal record. State limits may be lower than federal.

Field names used by the API: cargo_weight_lb, tiedown_count, wll_each_lb, cargo_length_ft, aggregate_wll_lb, required_wll_lb

WLL the marked rating of each tiedown (not breaking strength); the lowest-rated component governs each tiedown49 CFR 393.102