Suspension Insulator Uplift Check at a Low Point
In hilly country a suspension structure sitting in a sag between two higher structures can be lifted rather than loaded.
Example
You enter
- Span to the higher structure (ft) 500
- Elevation rise over that span (ft) 60
- Conductor weight (lb/ft) 1.094
- Horizontal tension, cold condition (lb) 5000
- Back span (ft, 0 to skip) 400
- Elevation rise over the back span (ft) 40
You get
- Vertical load low (lb) -326.5
- Vertical load at the high structure 873.5
- Low point of the curve -298.446
- Uplift tension (lb) 2279.17
- Structure vertical load (lb) 392.3
Details, formula, and sources
In hilly country a suspension structure sitting in a sag between two higher structures can be lifted rather than loaded, and uplift unseats a suspension clamp, inverts a post insulator, and is a listed cause of structure damage. An inclined span's weight does not split evenly: the horizontal tension acting along the sloped chord adds a downward component at the high support and an equal UPWARD component at the low one, so the vertical load at the low structure is half the conductor weight less that component. When the component wins, the load goes negative. A 500 ft span rising 60 ft at 1.094 lb/ft and a cold 5,000 lb of tension puts 273.5 lb of conductor weight against 600.0 lb of upward pull, for -326.5 lb: the structure is being lifted with 326 lb. The same arithmetic says where the low point of the curve sits, and it lands 298 ft OUTSIDE the span -- which is the geometric statement of the identical condition, because a span whose low point falls outside itself is a span pulling up at one end. The threshold is worth stating exactly: uplift begins when the tension reaches the weight per foot times the span squared, over twice the rise, which on that span is 2,279 lb, so anything above that lifts. The condition worsens in COLD weather, because cold means high tension and the tension is the term doing the lifting -- which is the opposite of the intuition built on clearance problems, where hot is the bad case. The check must be run at the structure against BOTH adjacent spans together, since the real vertical load there is the sum of what each side contributes; enter the back span and its rise and the net is reported. This is a static vertical-load check on the conductor at one condition. It does not size or select a suspension, tension, or hold-down assembly, evaluate insulator swing under wind, or address the longitudinal loads a hold-down arrangement introduces. It does not compute the tension -- enter the cold, high-tension governing case from the change-of-state calculation -- and it assumes the same horizontal tension in both adjacent spans, which is the ruling-span idealization and is weakest on exactly the steep, unequal spans where uplift occurs. The utility's construction standards, the applicable NESC edition, and the line designer govern.
V_low = w L / 2 - H h / L; V_high = w L / 2 + H h / L; low-point offset from the lower support x0 = L/2 - H h / (w L); uplift begins at H = w L^2 / (2 h).
The inclined-span vertical reaction relations as standard overhead line practice, by name. Cold, high tension is the governing case. The utility's construction standards, the applicable NESC edition, and the line designer govern.
A subtraction on span geometry and a tension the user supplies; no assembly table is reproduced.
Estimate. AHJ and licensed professional govern.
Field names used by the API: span_ft, elevation_rise_ft, weight_lb_per_ft, tension_lb, back_span_ft, back_span_rise_ft, vertical_load_low_lb, vertical_load_high_lb, low_point_offset_ft, uplift_tension_lb, structure_vertical_load_lb
- Cold and high tension governs the opposite of the clearance caseoverhead line practice
- Equal tension in both spans the ruling-span idealization, weakest on exactly these steep spansoverhead line practice
- No assembly is selected a tension assembly or hold-down is a design decisionthe utility's construction standards