Groove Weld Length for an Applied Load

L = load / (stress in ksi x 1000 x throat), with stress in ksi = 0.30 FEXX (ASD) or 0.75 x 0.60 FEXX (LRFD). A 100,000 lb LRFD load on a 0.25 in E70 PJP throat needs about 12.7 in. Round up, split between joint sides, and add for returns and minimum-length rules. AWS D1.1 / AISC 360 §J2; the WPS and engineer of record govern.

required_length = applied_load / (stress_ksi x 1000 x throat), the inverse of capacity = stress_ksi x 1000 x throat x length; stress_ksi = 0.30*FEXX (ASD) or 0.75*0.60*FEXX (LRFD); throat = CJP thinner part thickness or PJP WPS effective throat.

Groove weld (CJP / PJP) shear capacity (AISC 360 Table J2.5 weld-metal shear 0.60*FEXX on the effective throat), solved for the length, per AWS D1.1 Structural Welding Code and AISC 360 §J2, by name.

First-principles AISC J2 shear. A CJP weld with matching filler develops the base metal in tension/compression; the PJP effective throat is read off the qualified WPS. The WPS, weld inspector, and engineer of record govern.

Estimate. AHJ and licensed structural engineer govern.

Field names used by the API: applied_load_lb, weld_type, effective_throat_in, electrode, method, required_length_in, stress_ksi

• Effective throat CJP uses the thinner part thickness; PJP uses the WPS effective throat (groove depth less the AWS Table 3.1 reduction); user-suppliedAWS D1.1 Table 3.1
• Round up and detail round the length up, split between joint sides, add for returns and minimum-length rulesAWS D1.1