Joist Mid-Span Deflection
Mid-span deflection with L/360 and L/240 checks.
Example
You enter
- Uniform load (plf) 50
- Span (ft) 12
- E (psi) 1600000
- I (in⁴) 47.6
You get
- Mid-span deflection 0.3063 in
- Limit L over 360 (in) 0.4
- Limit L over 240 (in) 0.6
- Pass L over 360 Yes
- Pass L over 240 Yes
Details, formula, and sources
Mid-span deflection Δ = 5 × w × L⁴ / (384 × E × I) for uniformly loaded simple span. E and I from AWC NDS-2018 design values keyed to species / grade / size.
AWC NDS-2018 (National Design Specification for Wood Construction). IRC 2021 (International Residential Code). §R301.7.
Free at awc.org. Free read-only access at codes.iccsafe.org.
Estimate. AHJ and licensed structural engineer govern.
Field names used by the API: uniform_load_plf, span_ft, E_psi, I_in4, deflection_in, limit_L_over_360_in, limit_L_over_240_in, pass_L_over_360, pass_L_over_240
- Section properties S4S actual dimensions per AWC NDS SupplementAWC NDS-2018