Multiwire Branch Circuit (3-Wire) Voltage Drop

Voltage drop on a 120/240 V multiwire branch circuit, where two hot legs share one neutral.

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On a 120/240 3-wire the neutral carries the DIFFERENCE, so VD_A = R(2 I_A - I_B) and VD_B = R(2 I_B - I_A). Balanced, that collapses to half a two-wire circuit's drop because the neutral carries nothing. Badly unbalanced, the lightly loaded leg's drop goes NEGATIVE - it sits above nominal from neutral shift. 16 A against 4 A on 100 ft of 12 AWG: leg A 5.41 V, leg B rises 1.55 V.

Neutral current = |I_A - I_B|; with equal conductors of one-way resistance R, VD_A = R(2 I_A - I_B) and VD_B = R(2 I_B - I_A); balanced this is R x I, half a two-wire circuit's 2 R I.

Circuit analysis of a 120/240 V three-wire multiwire branch circuit; NEC 210.4(B) common-disconnect and neutral-continuity requirements named by section, no table reproduced.

The circuit analysis is elementary; conductor resistance is computed by this catalog's own resistance model from the size, material, and temperature entered.

Estimate. AHJ and licensed electrician govern. Verify against the NEC edition adopted in your jurisdiction.

Field names used by the API: awg, material, one_way_length_ft, load_a_amps, load_b_amps, source_volts, temperature_C, neutral_amps, vd_a_volts, vd_b_volts, balanced_vd, two_wire_vd

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