Terminal Velocity (Aerodynamic Drag)
The speed a falling object stops accelerating at, where drag balances weight.
Example
You enter
- Object weight W (lb) 180
- Frontal area A (ft²) 7
- Drag coefficient Cd 0.7
- Air density (lb/ft³) 0.0765
You get
- Terminal velocity (fps) 175.8
- Terminal velocity (mph) 119.9
Details, formula, and sources
V_t = sqrt(2 W/(rho_mass Cd A)), rho_mass = (air weight density)/g. A 180 lb skydiver at 7 ft^2 and Cd 0.7 terminals at the familiar 120 mph; a compact 5 lb tool near 140 mph, so over a short jobsite drop it is still accelerating (free-fall is right), but a sheet of plywood or a person tops out and falls no faster no matter the height. Heavy, compact, slick objects fall fast; light, bluff ones settle slowly. The distance/time to reach terminal, tumbling, and altitude density change are separate. Pairs with the free-fall drop and the drag force. A planning estimate; field conditions govern.
rho_mass = rho_weight/g; V_t = sqrt(2 W/(rho_mass Cd A)) (drag balances weight, W = 1/2 rho V^2 Cd A). g = 32.174 ft/s^2.
The terminal-velocity balance W = 1/2 rho V^2 Cd A solved for V (standard fluid mechanics), by name; the drag-limited counterpart to free-fall-drop.
The terminal-velocity relation is a standard published fluid-mechanics result; the weight, frontal area, drag coefficient, and air density are the user's inputs.
Estimate. AHJ and licensed professional govern.
Field names used by the API: weight_lb, frontal_area_ft2, drag_coefficient, air_density_lb_ft3, terminal_velocity_fps, terminal_velocity_mph
- Balance V_t = sqrt(2 W/(rho_mass Cd A)), drag equals weight at terminalfluid mechanics
- Constant Cd steady terminal for a constant drag coefficient in still airscope of this tile
- Scope distance/time to reach terminal, tumbling, and altitude density change are separatescope of this tile