Three-Phase Power
kW, kVA, and kVAR from line values and power factor.
Example
You enter
- Line-to-line voltage (V) 480
- Line current (A) 100
- Power factor 0.9
You get
- kVA 83.138
- kW 74.825
- kVAR 36.239
Details, formula, and sources
S = √3 × V_LL × I (apparent VA); P = S × pf (real W); Q = S × sin(acos(pf)) (reactive VAR).
Classical AC power theory; IEEE 141 (Red Book) by name.
IEEE-USA outreach materials free; IEEE 141 itself is licensed.
Estimate. AHJ and licensed electrician govern. Verify against the NEC edition adopted in your jurisdiction.
Field names used by the API: V_LL, I_L, pf, kVA, kW, kVAR
- Balanced load true unless user supplies imbalancecalculation convention