Cooling Coil Total Load from Enthalpy Difference
Q = 4.5 x CFM x (h_ent - h_lvg) Btu/hr, the full sensible-plus-latent heat a coil removes, from the moist-air enthalpy drop. 2,000 CFM across a 31.48 -> 22.97 Btu/lb drop -> 76,590 Btu/hr (6.38 tons), well above the dry-bulb-only estimate. A design aid; the coil rating governs.
Formula and source
Q = 4.5 x CFM x (h_ent - h_lvg) Btu/hr; tons = Q / 12000.
The total-heat coil-load relation from the ASHRAE Handbook - Fundamentals, by name.
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